x^2+8x-624=0

Solution for x^2+8x-624=0 equation:

x^2+8x-624=0

a = 1; b = 8; c = -624;
Δ = b2-4ac
Δ = 82-4·1·(-624)
Δ = 2560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2560}=\sqrt{256*10}=\sqrt{256}*\sqrt{10}=16\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-16\sqrt{10}}{2*1}=\frac{-8-16\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+16\sqrt{10}}{2*1}=\frac{-8+16\sqrt{10}}{2}
$